Base | Representation |
---|---|
bin | 10011101001111011000… |
… | …111111000001001001011 |
3 | 11210010100120212012221211 |
4 | 103221323013320021023 |
5 | 134112200430042413 |
6 | 2512255111313551 |
7 | 166404146262016 |
oct | 23517307701113 |
9 | 4703316765854 |
10 | 1350685393483 |
11 | 480905768538 |
12 | 19993197b8b7 |
13 | 9a4a4b6102a |
14 | 49532d3037d |
15 | 25203a5483d |
hex | 13a7b1f824b |
1350685393483 has 2 divisors, whose sum is σ = 1350685393484. Its totient is φ = 1350685393482.
The previous prime is 1350685393469. The next prime is 1350685393567. The reversal of 1350685393483 is 3843935860531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1350685393483 - 29 = 1350685392971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350685393403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675342696741 + 675342696742.
It is an arithmetic number, because the mean of its divisors is an integer number (675342696742).
Almost surely, 21350685393483 is an apocalyptic number.
1350685393483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350685393483 is an equidigital number, since it uses as much as digits as its factorization.
1350685393483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27993600, while the sum is 58.
The spelling of 1350685393483 in words is "one trillion, three hundred fifty billion, six hundred eighty-five million, three hundred ninety-three thousand, four hundred eighty-three".
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