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135069481 is a prime number
BaseRepresentation
bin10000000110011…
…11111100101001
3100102011020111101
420003033330221
5234034210411
621223001401
73230033401
oct1003177451
9312136441
10135069481
116a274778
1239299261
1321ca2091
1413d1d801
15bcd08c1
hex80cff29

135069481 has 2 divisors, whose sum is σ = 135069482. Its totient is φ = 135069480.

The previous prime is 135069419. The next prime is 135069503. The reversal of 135069481 is 184960531.

135069481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91298025 + 43771456 = 9555^2 + 6616^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135069481 is a prime.

It is a super-2 number, since 2×1350694812 = 36487529395218722, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135069481.

It is not a weakly prime, because it can be changed into another prime (135069581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67534740 + 67534741.

It is an arithmetic number, because the mean of its divisors is an integer number (67534741).

Almost surely, 2135069481 is an apocalyptic number.

It is an amenable number.

135069481 is a deficient number, since it is larger than the sum of its proper divisors (1).

135069481 is an equidigital number, since it uses as much as digits as its factorization.

135069481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 37.

The square root of 135069481 is about 11621.9396401805. The cubic root of 135069481 is about 513.0807769375.

The spelling of 135069481 in words is "one hundred thirty-five million, sixty-nine thousand, four hundred eighty-one".