Search a number
-
+
135074103793 = 294657727717
BaseRepresentation
bin111110111001100001…
…0110100000111110001
3110220122112202102110221
41331303002310013301
54203112432310133
6142015134453041
712521155636606
oct1756302640761
9426575672427
10135074103793
11523148a0442
1222218064181
13c9781aab05
14677533a6ad
1537a8556a2d
hex1f730b41f1

135074103793 has 4 divisors (see below), whose sum is σ = 139731831540. Its totient is φ = 130416376048.

The previous prime is 135074103779. The next prime is 135074103833. The reversal of 135074103793 is 397301470531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 397301470531 = 756757352933.

It can be written as a sum of positive squares in 2 ways, for example, as 81809156529 + 53264947264 = 286023^2 + 230792^2 .

It is a cyclic number.

It is not a de Polignac number, because 135074103793 - 213 = 135074095601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135074103893) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2328863830 + ... + 2328863887.

It is an arithmetic number, because the mean of its divisors is an integer number (34932957885).

Almost surely, 2135074103793 is an apocalyptic number.

It is an amenable number.

135074103793 is a deficient number, since it is larger than the sum of its proper divisors (4657727747).

135074103793 is an equidigital number, since it uses as much as digits as its factorization.

135074103793 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4657727746.

The product of its (nonzero) digits is 238140, while the sum is 43.

The spelling of 135074103793 in words is "one hundred thirty-five billion, seventy-four million, one hundred three thousand, seven hundred ninety-three".

Divisors: 1 29 4657727717 135074103793