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1351022510113 is a prime number
BaseRepresentation
bin10011101010001111001…
…101111000000000100001
311210011020002012112000221
4103222033031320000201
5134113343230310423
62512352353043041
7166415411600233
oct23521715700041
94704202175027
101351022510113
11480a68a93221
12199a06856481
139a529956123
1449565a06253
1525223445e5d
hex13a8f378021

1351022510113 has 2 divisors, whose sum is σ = 1351022510114. Its totient is φ = 1351022510112.

The previous prime is 1351022510107. The next prime is 1351022510221. The reversal of 1351022510113 is 3110152201531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 724689556369 + 626332953744 = 851287^2 + 791412^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351022510113 - 237 = 1213583556641 is a prime.

It is not a weakly prime, because it can be changed into another prime (1351022517113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675511255056 + 675511255057.

It is an arithmetic number, because the mean of its divisors is an integer number (675511255057).

Almost surely, 21351022510113 is an apocalyptic number.

It is an amenable number.

1351022510113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351022510113 is an equidigital number, since it uses as much as digits as its factorization.

1351022510113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 1351022510113 its reverse (3110152201531), we get a palindrome (4461174711644).

The spelling of 1351022510113 in words is "one trillion, three hundred fifty-one billion, twenty-two million, five hundred ten thousand, one hundred thirteen".