Base | Representation |
---|---|
bin | 10011101010001111111… |
… | …111101010111110110001 |
3 | 11210011020222202201112111 |
4 | 103222033333222332301 |
5 | 134113410101021303 |
6 | 2512353540525321 |
7 | 166415630546125 |
oct | 23521777527661 |
9 | 4704228681474 |
10 | 1351035563953 |
11 | 480a75399819 |
12 | 199a0b0b0841 |
13 | 9a52c5769aa |
14 | 49567643585 |
15 | 25224673b6d |
hex | 13a8ffeafb1 |
1351035563953 has 2 divisors, whose sum is σ = 1351035563954. Its totient is φ = 1351035563952.
The previous prime is 1351035563947. The next prime is 1351035564017. The reversal of 1351035563953 is 3593655301531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1334884458384 + 16151105569 = 1155372^2 + 127087^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351035563953 - 225 = 1351002009521 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1351035563897 and 1351035563906.
It is not a weakly prime, because it can be changed into another prime (1351035563653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675517781976 + 675517781977.
It is an arithmetic number, because the mean of its divisors is an integer number (675517781977).
Almost surely, 21351035563953 is an apocalyptic number.
It is an amenable number.
1351035563953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351035563953 is an equidigital number, since it uses as much as digits as its factorization.
1351035563953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2733750, while the sum is 49.
The spelling of 1351035563953 in words is "one trillion, three hundred fifty-one billion, thirty-five million, five hundred sixty-three thousand, nine hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •