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1351107540457 = 2343157663247
BaseRepresentation
bin10011101010010100010…
…010001111010111101001
311210011110000012111201221
4103222110102033113221
5134114032012243312
62512405031342041
7166420463414143
oct23522422172751
94704400174657
101351107540457
11481001a8a834
12199a2b221921
139a54145803c
144957301bc93
152522ab40207
hex13a9448f5e9

1351107540457 has 4 divisors (see below), whose sum is σ = 1351165227136. Its totient is φ = 1351049853780.

The previous prime is 1351107540451. The next prime is 1351107540493. The reversal of 1351107540457 is 7540457011531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1351107540457 - 23 = 1351107540449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1351107540451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28808193 + ... + 28855054.

It is an arithmetic number, because the mean of its divisors is an integer number (337791306784).

Almost surely, 21351107540457 is an apocalyptic number.

It is an amenable number.

1351107540457 is a deficient number, since it is larger than the sum of its proper divisors (57686679).

1351107540457 is an equidigital number, since it uses as much as digits as its factorization.

1351107540457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57686678.

The product of its (nonzero) digits is 294000, while the sum is 43.

The spelling of 1351107540457 in words is "one trillion, three hundred fifty-one billion, one hundred seven million, five hundred forty thousand, four hundred fifty-seven".

Divisors: 1 23431 57663247 1351107540457