Base | Representation |
---|---|
bin | 1100010010011100111001… |
… | …0111001100111000101001 |
3 | 1202211122121011221001001110 |
4 | 3010213032113030320221 |
5 | 3232331300342201010 |
6 | 44422532431140533 |
7 | 2563101334636503 |
oct | 304471627147051 |
9 | 52748534831043 |
10 | 13511134334505 |
11 | 433a049108535 |
12 | 162266b674749 |
13 | 77012c8061b2 |
14 | 349d29cc6d73 |
15 | 1866c7a42120 |
hex | c49ce5cce29 |
13511134334505 has 32 divisors (see below), whose sum is σ = 22891855795200. Its totient is φ = 6785800062912.
The previous prime is 13511134334461. The next prime is 13511134334507. The reversal of 13511134334505 is 50543343111531.
13511134334505 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13511134334505 - 211 = 13511134332457 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13511134334507) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 141890995 + ... + 141986184.
It is an arithmetic number, because the mean of its divisors is an integer number (715370493600).
Almost surely, 213511134334505 is an apocalyptic number.
13511134334505 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13511134334505 is a deficient number, since it is larger than the sum of its proper divisors (9380721460695).
13511134334505 is a wasteful number, since it uses less digits than its factorization.
13511134334505 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283877373.
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 13511134334505 in words is "thirteen trillion, five hundred eleven billion, one hundred thirty-four million, three hundred thirty-four thousand, five hundred five".
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