Base | Representation |
---|---|
bin | 10011101010010100101… |
… | …100111101011110010001 |
3 | 11210011110111101101012222 |
4 | 103222110230331132101 |
5 | 134114040310420131 |
6 | 2512405441430425 |
7 | 166420610066522 |
oct | 23522454753621 |
9 | 4704414341188 |
10 | 1351114545041 |
11 | 481005a34448 |
12 | 199a3163b415 |
13 | 9a542a3b371 |
14 | 49573d22849 |
15 | 2522b57587b |
hex | 13a94b3d791 |
1351114545041 has 2 divisors, whose sum is σ = 1351114545042. Its totient is φ = 1351114545040.
The previous prime is 1351114544981. The next prime is 1351114545089. The reversal of 1351114545041 is 1405454111531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 878210762641 + 472903782400 = 937129^2 + 687680^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351114545041 - 230 = 1350040803217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1351114544992 and 1351114545010.
It is not a weakly prime, because it can be changed into another prime (1351114565041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675557272520 + 675557272521.
It is an arithmetic number, because the mean of its divisors is an integer number (675557272521).
Almost surely, 21351114545041 is an apocalyptic number.
It is an amenable number.
1351114545041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351114545041 is an equidigital number, since it uses as much as digits as its factorization.
1351114545041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 35.
Adding to 1351114545041 its reverse (1405454111531), we get a palindrome (2756568656572).
The spelling of 1351114545041 in words is "one trillion, three hundred fifty-one billion, one hundred fourteen million, five hundred forty-five thousand, forty-one".
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