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1351114726243 is a prime number
BaseRepresentation
bin10011101010010100101…
…101101001101101100011
311210011110111201120210011
4103222110231221231203
5134114040332214433
62512405445345351
7166420611453022
oct23522455515543
94704414646704
101351114726243
114810060485a7
12199a31708257
139a542aa2999
1449573d6c8b9
152522b5ae3cd
hex13a94b69b63

1351114726243 has 2 divisors, whose sum is σ = 1351114726244. Its totient is φ = 1351114726242.

The previous prime is 1351114726237. The next prime is 1351114726271. The reversal of 1351114726243 is 3426274111531.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1351114726243 is a prime.

It is a super-2 number, since 2×13511147262432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1351114726196 and 1351114726205.

It is not a weakly prime, because it can be changed into another prime (1351114726343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675557363121 + 675557363122.

It is an arithmetic number, because the mean of its divisors is an integer number (675557363122).

Almost surely, 21351114726243 is an apocalyptic number.

1351114726243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351114726243 is an equidigital number, since it uses as much as digits as its factorization.

1351114726243 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120960, while the sum is 40.

Adding to 1351114726243 its reverse (3426274111531), we get a palindrome (4777388837774).

The spelling of 1351114726243 in words is "one trillion, three hundred fifty-one billion, one hundred fourteen million, seven hundred twenty-six thousand, two hundred forty-three".