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1351120076737 is a prime number
BaseRepresentation
bin10011101010010101000…
…010000011111111000001
311210011110212210102021121
4103222111002003333001
5134114043214423422
62512410200152241
7166421005106104
oct23522502037701
94704425712247
101351120076737
114810090724a2
12199a33468681
139a543c27162
144957496273b
152522bcb98c7
hex13a95083fc1

1351120076737 has 2 divisors, whose sum is σ = 1351120076738. Its totient is φ = 1351120076736.

The previous prime is 1351120076729. The next prime is 1351120076743. The reversal of 1351120076737 is 7376700211531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1247385194496 + 103734882241 = 1116864^2 + 322079^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351120076737 - 23 = 1351120076729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1351120076693 and 1351120076702.

It is not a weakly prime, because it can be changed into another prime (1351120076797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675560038368 + 675560038369.

It is an arithmetic number, because the mean of its divisors is an integer number (675560038369).

Almost surely, 21351120076737 is an apocalyptic number.

It is an amenable number.

1351120076737 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351120076737 is an equidigital number, since it uses as much as digits as its factorization.

1351120076737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 185220, while the sum is 43.

The spelling of 1351120076737 in words is "one trillion, three hundred fifty-one billion, one hundred twenty million, seventy-six thousand, seven hundred thirty-seven".