Base | Representation |
---|---|
bin | 111110111010101010… |
… | …0111010001000111011 |
3 | 110220202012211011000022 |
4 | 1331311110322020323 |
5 | 4203202233321332 |
6 | 142023023401055 |
7 | 12522132314621 |
oct | 1756524721073 |
9 | 426665734008 |
10 | 135112401467 |
11 | 5233447900a |
12 | 22228a5318b |
13 | c9830c9864 |
14 | 677a469511 |
15 | 37ababe212 |
hex | 1f7553a23b |
135112401467 has 2 divisors, whose sum is σ = 135112401468. Its totient is φ = 135112401466.
The previous prime is 135112401439. The next prime is 135112401481. The reversal of 135112401467 is 764104211531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135112401467 - 232 = 130817434171 is a prime.
It is a super-2 number, since 2×1351124014672 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135112401427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67556200733 + 67556200734.
It is an arithmetic number, because the mean of its divisors is an integer number (67556200734).
Almost surely, 2135112401467 is an apocalyptic number.
135112401467 is a deficient number, since it is larger than the sum of its proper divisors (1).
135112401467 is an equidigital number, since it uses as much as digits as its factorization.
135112401467 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 135112401467 its reverse (764104211531), we get a palindrome (899216612998).
The spelling of 135112401467 in words is "one hundred thirty-five billion, one hundred twelve million, four hundred one thousand, four hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •