135114343201 has 2 divisors, whose sum is σ = 135114343202. Its totient is φ = 135114343200.

The previous prime is 135114343171. The next prime is 135114343219. The reversal of 135114343201 is 102343411531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128146100625 + 6968242576 = 357975^2 + 83476^2 .

It is a cyclic number.

It is not a de Polignac number, because 135114343201 - 2⁹ = 135114342689 is a prime.

It is a super-3 number, since 3×135114343201³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 135114343201.

It is not a weakly prime, because it can be changed into another prime (135114343241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67557171600 + 67557171601.

It is an arithmetic number, because the mean of its divisors is an integer number (67557171601).

Almost surely, 2^135114343201 is an apocalyptic number.

It is an amenable number.

135114343201 is a deficient number, since it is larger than the sum of its proper divisors (1).

135114343201 is an equidigital number, since it uses as much as digits as its factorization.

135114343201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 135114343201 its reverse (102343411531), we get a palindrome (237457754732).

The spelling of 135114343201 in words is "one hundred thirty-five billion, one hundred fourteen million, three hundred forty-three thousand, two hundred one".