135114415003 has 2 divisors, whose sum is σ = 135114415004. Its totient is φ = 135114415002.

The previous prime is 135114414979. The next prime is 135114415013. The reversal of 135114415003 is 300514411531.

It is a strong prime.

It is an emirp because it is prime and its reverse (300514411531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-135114415003 is a prime.

It is a super-2 number, since 2×135114415003² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135114415013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67557207501 + 67557207502.

It is an arithmetic number, because the mean of its divisors is an integer number (67557207502).

Almost surely, 2^135114415003 is an apocalyptic number.

135114415003 is a deficient number, since it is larger than the sum of its proper divisors (1).

135114415003 is an equidigital number, since it uses as much as digits as its factorization.

135114415003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 135114415003 its reverse (300514411531), we get a palindrome (435628826534).

The spelling of 135114415003 in words is "one hundred thirty-five billion, one hundred fourteen million, four hundred fifteen thousand, three".