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135124353041 = 1312122748593
BaseRepresentation
bin111110111011000001…
…0100000000000010001
3110220210001022100111012
41331312002200000101
54203213313244131
6142024131500305
712522336023066
oct1756602400021
9426701270435
10135124353041
11523401a1447
1222230a57695
13c9857227b2
14677bc9ac6d
1537acb8052b
hex1f760a0011

135124353041 has 8 divisors (see below), whose sum is σ = 136165053024. Its totient is φ = 134083792960.

The previous prime is 135124353031. The next prime is 135124353061. The reversal of 135124353041 is 140353421531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135124353041 - 222 = 135120158737 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 135124352989 and 135124353007.

It is not an unprimeable number, because it can be changed into a prime (135124353031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2756441 + ... + 2805033.

It is an arithmetic number, because the mean of its divisors is an integer number (17020631628).

Almost surely, 2135124353041 is an apocalyptic number.

It is an amenable number.

135124353041 is a deficient number, since it is larger than the sum of its proper divisors (1040699983).

135124353041 is a wasteful number, since it uses less digits than its factorization.

135124353041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69951.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 135124353041 its reverse (140353421531), we get a palindrome (275477774572).

The spelling of 135124353041 in words is "one hundred thirty-five billion, one hundred twenty-four million, three hundred fifty-three thousand, forty-one".

Divisors: 1 131 21227 48593 2780737 6365683 1031483611 135124353041