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1351344132044 = 22812341590057
BaseRepresentation
bin10011101010100010011…
…000110000111111001100
311210012001111101121101022
4103222202120300333030
5134120023044211134
62512444322333312
7166426365412424
oct23524230607714
94705044347338
101351344132044
11481113595575
12199a964ba238
139a57b48466a
1449596607484
15252417c652e
hex13aa2630fcc

1351344132044 has 12 divisors (see below), whose sum is σ = 2365143418344. Its totient is φ = 675588869664.

The previous prime is 1351344132041. The next prime is 1351344132113. The reversal of 1351344132044 is 4402314431531.

It is a super-4 number, since 4×13513441320444 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1351344131995 and 1351344132013.

It is not an unprimeable number, because it can be changed into a prime (1351344132041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20762537 + ... + 20827520.

It is an arithmetic number, because the mean of its divisors is an integer number (197095284862).

Almost surely, 21351344132044 is an apocalyptic number.

It is an amenable number.

1351344132044 is a deficient number, since it is larger than the sum of its proper divisors (1013799286300).

1351344132044 is a wasteful number, since it uses less digits than its factorization.

1351344132044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41598184 (or 41598182 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 1351344132044 its reverse (4402314431531), we get a palindrome (5753658563575).

The spelling of 1351344132044 in words is "one trillion, three hundred fifty-one billion, three hundred forty-four million, one hundred thirty-two thousand, forty-four".

Divisors: 1 2 4 8123 16246 32492 41590057 83180114 166360228 337836033011 675672066022 1351344132044