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13513454401 is a prime number
BaseRepresentation
bin11001001010111011…
…01111001101000001
31021212202221121111011
430211131233031001
5210133421020101
610112532120521
7655606316146
oct144535571501
937782847434
1013513454401
115804aa1337
122751766141
131374887a85
14922a243cd
15541576751
hex32576f341

13513454401 has 2 divisors, whose sum is σ = 13513454402. Its totient is φ = 13513454400.

The previous prime is 13513454387. The next prime is 13513454419. The reversal of 13513454401 is 10445431531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7013225025 + 6500229376 = 83745^2 + 80624^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13513454401 is a prime.

It is a super-2 number, since 2×135134544012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13513454441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6756727200 + 6756727201.

It is an arithmetic number, because the mean of its divisors is an integer number (6756727201).

Almost surely, 213513454401 is an apocalyptic number.

It is an amenable number.

13513454401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13513454401 is an equidigital number, since it uses as much as digits as its factorization.

13513454401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13513454401 its reverse (10445431531), we get a palindrome (23958885932).

The spelling of 13513454401 in words is "thirteen billion, five hundred thirteen million, four hundred fifty-four thousand, four hundred one".