Base | Representation |
---|---|
bin | 11001001011000011… |
… | …00010100111001011 |
3 | 1021212211211021010011 |
4 | 30211201202213023 |
5 | 210134144421103 |
6 | 10113005332351 |
7 | 655620640645 |
oct | 144541424713 |
9 | 37784737104 |
10 | 13514451403 |
11 | 5805612402 |
12 | 2751b670b7 |
13 | 1374b4680b |
14 | 922c03895 |
15 | 5416c1d6d |
hex | 3258629cb |
13514451403 has 2 divisors, whose sum is σ = 13514451404. Its totient is φ = 13514451402.
The previous prime is 13514451361. The next prime is 13514451407. The reversal of 13514451403 is 30415441531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13514451403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13514451407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6757225701 + 6757225702.
It is an arithmetic number, because the mean of its divisors is an integer number (6757225702).
Almost surely, 213514451403 is an apocalyptic number.
13514451403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13514451403 is an equidigital number, since it uses as much as digits as its factorization.
13514451403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13514451403 its reverse (30415441531), we get a palindrome (43929892934).
The spelling of 13514451403 in words is "thirteen billion, five hundred fourteen million, four hundred fifty-one thousand, four hundred three".
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