Base | Representation |
---|---|
bin | 10011101010110111111… |
… | …010111111100101000001 |
3 | 11210012222200020020211212 |
4 | 103222313322333211001 |
5 | 134121243042114431 |
6 | 2512544230215505 |
7 | 166441343356322 |
oct | 23526772774501 |
9 | 4705880206755 |
10 | 1351705426241 |
11 | 481289524215 |
12 | 199b774b4595 |
13 | 9a608293501 |
14 | 495cc5b4449 |
15 | 2526339172b |
hex | 13ab7ebf941 |
1351705426241 has 2 divisors, whose sum is σ = 1351705426242. Its totient is φ = 1351705426240.
The previous prime is 1351705426213. The next prime is 1351705426261. The reversal of 1351705426241 is 1426245071531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 914624449600 + 437080976641 = 956360^2 + 661121^2 .
It is a cyclic number.
It is not a de Polignac number, because 1351705426241 - 226 = 1351638317377 is a prime.
It is not a weakly prime, because it can be changed into another prime (1351705426261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675852713120 + 675852713121.
It is an arithmetic number, because the mean of its divisors is an integer number (675852713121).
Almost surely, 21351705426241 is an apocalyptic number.
It is an amenable number.
1351705426241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1351705426241 is an equidigital number, since it uses as much as digits as its factorization.
1351705426241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 41.
The spelling of 1351705426241 in words is "one trillion, three hundred fifty-one billion, seven hundred five million, four hundred twenty-six thousand, two hundred forty-one".
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