Base | Representation |
---|---|
bin | 10011101011001010011… |
… | …110010011001001011011 |
3 | 11210020210100220010211111 |
4 | 103223022132103021123 |
5 | 134122412231440243 |
6 | 2513035145241151 |
7 | 166452143042353 |
oct | 23531236231133 |
9 | 4706710803744 |
10 | 1352016671323 |
11 | 48142918925a |
12 | 19a0437931b7 |
13 | 9a6578ca7b6 |
14 | 4961ba73b63 |
15 | 2528087239d |
hex | 13aca79325b |
1352016671323 has 2 divisors, whose sum is σ = 1352016671324. Its totient is φ = 1352016671322.
The previous prime is 1352016671273. The next prime is 1352016671339. The reversal of 1352016671323 is 3231766102531.
It is a strong prime.
It is an emirp because it is prime and its reverse (3231766102531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1352016671323 - 233 = 1343426736731 is a prime.
It is not a weakly prime, because it can be changed into another prime (1352016971323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676008335661 + 676008335662.
It is an arithmetic number, because the mean of its divisors is an integer number (676008335662).
Almost surely, 21352016671323 is an apocalyptic number.
1352016671323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1352016671323 is an equidigital number, since it uses as much as digits as its factorization.
1352016671323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 1352016671323 in words is "one trillion, three hundred fifty-two billion, sixteen million, six hundred seventy-one thousand, three hundred twenty-three".
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