Base | Representation |
---|---|
bin | 1100010011000011010011… |
… | …1001000001110001011011 |
3 | 1202212122012201011021020021 |
4 | 3010300310321001301123 |
5 | 3233013404232200012 |
6 | 44431355452011311 |
7 | 2563614666104113 |
oct | 304606471016133 |
9 | 52778181137207 |
10 | 13521444412507 |
11 | 434345995a759 |
12 | 1624668460b37 |
13 | 7710b380c675 |
14 | 34a6272c4043 |
15 | 186accc50007 |
hex | c4c34e41c5b |
13521444412507 has 2 divisors, whose sum is σ = 13521444412508. Its totient is φ = 13521444412506.
The previous prime is 13521444412499. The next prime is 13521444412573. The reversal of 13521444412507 is 70521444412531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13521444412507 - 23 = 13521444412499 is a prime.
It is not a weakly prime, because it can be changed into another prime (13521444416507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760722206253 + 6760722206254.
It is an arithmetic number, because the mean of its divisors is an integer number (6760722206254).
Almost surely, 213521444412507 is an apocalyptic number.
13521444412507 is a deficient number, since it is larger than the sum of its proper divisors (1).
13521444412507 is an equidigital number, since it uses as much as digits as its factorization.
13521444412507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 537600, while the sum is 43.
The spelling of 13521444412507 in words is "thirteen trillion, five hundred twenty-one billion, four hundred forty-four million, four hundred twelve thousand, five hundred seven".
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