Base | Representation |
---|---|
bin | 11001001011111100… |
… | …10101110001110011 |
3 | 1021220101000211020021 |
4 | 30211332111301303 |
5 | 210143113013021 |
6 | 10113435224311 |
7 | 656042053321 |
oct | 144576256163 |
9 | 37811024207 |
10 | 13522001011 |
11 | 58098a9552 |
12 | 27545a8097 |
13 | 137658ac3c |
14 | 923c0ad11 |
15 | 5421b3c41 |
hex | 325f95c73 |
13522001011 has 4 divisors (see below), whose sum is σ = 13958194624. Its totient is φ = 13085807400.
The previous prime is 13522000981. The next prime is 13522001021. The reversal of 13522001011 is 11010022531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13522001011 - 213 = 13521992819 is a prime.
It is a super-2 number, since 2×135220010112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13522001021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218096760 + ... + 218096821.
It is an arithmetic number, because the mean of its divisors is an integer number (3489548656).
Almost surely, 213522001011 is an apocalyptic number.
13522001011 is a deficient number, since it is larger than the sum of its proper divisors (436193613).
13522001011 is an equidigital number, since it uses as much as digits as its factorization.
13522001011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436193612.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 13522001011 its reverse (11010022531), we get a palindrome (24532023542).
The spelling of 13522001011 in words is "thirteen billion, five hundred twenty-two million, one thousand, eleven".
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