Search a number
-
+
13523116652203 = 31197134334731
BaseRepresentation
bin1100010011001001100010…
…0100000111011010101011
31202212210112020202211211211
43010302120210013122223
53233030320330332303
644432233425533551
72564004302646364
oct304623044073253
952783466684754
1013523116652203
114344137892134
121624a544a42b7
137712bc0b9502
1434a745420b6b
15186b7996d66d
hexc4c989076ab

13523116652203 has 4 divisors (see below), whose sum is σ = 13523124106648. Its totient is φ = 13523109197760.

The previous prime is 13523116652099. The next prime is 13523116652219. The reversal of 13523116652203 is 30225661132531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13523116652203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13523116652263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 952348 + ... + 5287078.

It is an arithmetic number, because the mean of its divisors is an integer number (3380781026662).

Almost surely, 213523116652203 is an apocalyptic number.

13523116652203 is a deficient number, since it is larger than the sum of its proper divisors (7454445).

13523116652203 is an equidigital number, since it uses as much as digits as its factorization.

13523116652203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7454444.

The product of its (nonzero) digits is 194400, while the sum is 40.

Adding to 13523116652203 its reverse (30225661132531), we get a palindrome (43748777784734).

The spelling of 13523116652203 in words is "thirteen trillion, five hundred twenty-three billion, one hundred sixteen million, six hundred fifty-two thousand, two hundred three".

Divisors: 1 3119713 4334731 13523116652203