13523400403 has 4 divisors (see below), whose sum is σ = 13662817000. Its totient is φ = 13383983808.

The previous prime is 13523400389. The next prime is 13523400409. The reversal of 13523400403 is 30400432531.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30400432531 = 7 ⋅4342918933.

It is a cyclic number.

It is not a de Polignac number, because 13523400403 - 2²¹ = 13521303251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13523400409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69708153 + ... + 69708346.

It is an arithmetic number, because the mean of its divisors is an integer number (3415704250).

Almost surely, 2^13523400403 is an apocalyptic number.

13523400403 is a deficient number, since it is larger than the sum of its proper divisors (139416597).

13523400403 is an equidigital number, since it uses as much as digits as its factorization.

13523400403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139416596.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 13523400403 its reverse (30400432531), we get a palindrome (43923832934).

The spelling of 13523400403 in words is "thirteen billion, five hundred twenty-three million, four hundred thousand, four hundred three".