Base | Representation |
---|---|
bin | 111110111110010010… |
… | …1001101010111011011 |
3 | 110221001200211211122020 |
4 | 1331330211031113123 |
5 | 4203424413140120 |
6 | 142043052225523 |
7 | 12525141003645 |
oct | 1757445152733 |
9 | 427050754566 |
10 | 135234115035 |
11 | 52397150238 |
12 | 2226176b2a3 |
13 | c9a23a3716 |
14 | 678c6ad895 |
15 | 37b7612640 |
hex | 1f7c94d5db |
135234115035 has 16 divisors (see below), whose sum is σ = 216467147520. Its totient is φ = 72094006880.
The previous prime is 135234115001. The next prime is 135234115061. The reversal of 135234115035 is 530511432531.
It is not a de Polignac number, because 135234115035 - 27 = 135234114907 is a prime.
It is a super-2 number, since 2×1352341150352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 135234114987 and 135234115005.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1892151 + ... + 1962320.
It is an arithmetic number, because the mean of its divisors is an integer number (13529196720).
Almost surely, 2135234115035 is an apocalyptic number.
135234115035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135234115035 is a deficient number, since it is larger than the sum of its proper divisors (81233032485).
135234115035 is a wasteful number, since it uses less digits than its factorization.
135234115035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3856818.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 135234115035 its reverse (530511432531), we get a palindrome (665745547566).
The spelling of 135234115035 in words is "one hundred thirty-five billion, two hundred thirty-four million, one hundred fifteen thousand, thirty-five".
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