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135235049953 is a prime number
BaseRepresentation
bin111110111110010100…
…0110001100111100001
3110221001202121100002211
41331330220301213201
54203430133044303
6142043124242121
712525151646443
oct1757450614741
9427052540084
10135235049953
11523977296a3
1222261b40341
13c9a2640123
14678c874493
1537b774966d
hex1f7ca319e1

135235049953 has 2 divisors, whose sum is σ = 135235049954. Its totient is φ = 135235049952.

The previous prime is 135235049909. The next prime is 135235050059. The reversal of 135235049953 is 359940532531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94613453649 + 40621596304 = 307593^2 + 201548^2 .

It is a cyclic number.

It is not a de Polignac number, because 135235049953 - 29 = 135235049441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135235049897 and 135235049906.

It is not a weakly prime, because it can be changed into another prime (135235049903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67617524976 + 67617524977.

It is an arithmetic number, because the mean of its divisors is an integer number (67617524977).

Almost surely, 2135235049953 is an apocalyptic number.

It is an amenable number.

135235049953 is a deficient number, since it is larger than the sum of its proper divisors (1).

135235049953 is an equidigital number, since it uses as much as digits as its factorization.

135235049953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187000, while the sum is 49.

The spelling of 135235049953 in words is "one hundred thirty-five billion, two hundred thirty-five million, forty-nine thousand, nine hundred fifty-three".