Base | Representation |
---|---|
bin | 11001001100010100… |
… | …10001111011111001 |
3 | 1021220120220211202211 |
4 | 30212022101323321 |
5 | 210144413143001 |
6 | 10114030255121 |
7 | 656110500544 |
oct | 144612217371 |
9 | 37816824684 |
10 | 13525131001 |
11 | 5810647118 |
12 | 27556574a1 |
13 | 13771157c5 |
14 | 9243c385b |
15 | 5425d1351 |
hex | 326291ef9 |
13525131001 has 2 divisors, whose sum is σ = 13525131002. Its totient is φ = 13525131000.
The previous prime is 13525130987. The next prime is 13525131043. The reversal of 13525131001 is 10013152531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12476666601 + 1048464400 = 111699^2 + 32380^2 .
It is a cyclic number.
It is not a de Polignac number, because 13525131001 - 27 = 13525130873 is a prime.
It is a super-2 number, since 2×135251310012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13525131601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762565500 + 6762565501.
It is an arithmetic number, because the mean of its divisors is an integer number (6762565501).
Almost surely, 213525131001 is an apocalyptic number.
It is an amenable number.
13525131001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13525131001 is an equidigital number, since it uses as much as digits as its factorization.
13525131001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 13525131001 its reverse (10013152531), we get a palindrome (23538283532).
The spelling of 13525131001 in words is "thirteen billion, five hundred twenty-five million, one hundred thirty-one thousand, one".
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