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1352531511481 is a prime number
BaseRepresentation
bin10011101011101001001…
…010010000100010111001
311210022010020122201202111
4103223221022100202321
5134124441031331411
62513202220132321
7166500664105153
oct23535112204271
94708106581674
101352531511481
11481672861297
1219a1680970a1
139a70a47a547
144966a1adad3
15252b0b6c721
hex13ae92908b9

1352531511481 has 2 divisors, whose sum is σ = 1352531511482. Its totient is φ = 1352531511480.

The previous prime is 1352531511427. The next prime is 1352531511553. The reversal of 1352531511481 is 1841151352531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1229692477225 + 122839034256 = 1108915^2 + 350484^2 .

It is a cyclic number.

It is not a de Polignac number, because 1352531511481 - 29 = 1352531510969 is a prime.

It is a super-2 number, since 2×13525315114812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1352531571481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676265755740 + 676265755741.

It is an arithmetic number, because the mean of its divisors is an integer number (676265755741).

Almost surely, 21352531511481 is an apocalyptic number.

It is an amenable number.

1352531511481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352531511481 is an equidigital number, since it uses as much as digits as its factorization.

1352531511481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72000, while the sum is 40.

The spelling of 1352531511481 in words is "one trillion, three hundred fifty-two billion, five hundred thirty-one million, five hundred eleven thousand, four hundred eighty-one".