Search a number
-
+
1352551752553 is a prime number
BaseRepresentation
bin10011101011101010010…
…111011110001101101001
311210022011122202002021211
4103223222113132031221
5134130011222040203
62513204222033121
7166501331130061
oct23535227361551
94708148662254
101352551752553
11481683226751
1219a172a187a1
139a711716601
144966cb5c3a1
15252b2819c6d
hex13aea5de369

1352551752553 has 2 divisors, whose sum is σ = 1352551752554. Its totient is φ = 1352551752552.

The previous prime is 1352551752533. The next prime is 1352551752569. The reversal of 1352551752553 is 3552571552531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 840544243344 + 512007509209 = 916812^2 + 715547^2 .

It is an emirp because it is prime and its reverse (3552571552531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1352551752553 - 225 = 1352518198121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1352551752497 and 1352551752506.

It is not a weakly prime, because it can be changed into another prime (1352551752533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676275876276 + 676275876277.

It is an arithmetic number, because the mean of its divisors is an integer number (676275876277).

Almost surely, 21352551752553 is an apocalyptic number.

It is an amenable number.

1352551752553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1352551752553 is an equidigital number, since it uses as much as digits as its factorization.

1352551752553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3937500, while the sum is 49.

The spelling of 1352551752553 in words is "one trillion, three hundred fifty-two billion, five hundred fifty-one million, seven hundred fifty-two thousand, five hundred fifty-three".