Base | Representation |
---|---|
bin | 10011101011101010110… |
… | …100011100100100101011 |
3 | 11210022012012000222022002 |
4 | 103223222310130210223 |
5 | 134130020143114021 |
6 | 2513205052521215 |
7 | 166501452523214 |
oct | 23535264344453 |
9 | 4708165028262 |
10 | 1352559348011 |
11 | 481687544293 |
12 | 19a17548020b |
13 | 9a713175871 |
14 | 4966db7840b |
15 | 252b331a50b |
hex | 13aead1c92b |
1352559348011 has 2 divisors, whose sum is σ = 1352559348012. Its totient is φ = 1352559348010.
The previous prime is 1352559348001. The next prime is 1352559348029. The reversal of 1352559348011 is 1108439552531.
It is a weak prime.
It is an emirp because it is prime and its reverse (1108439552531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1352559348011 is a prime.
It is a super-2 number, since 2×13525593480112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1352559348001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676279674005 + 676279674006.
It is an arithmetic number, because the mean of its divisors is an integer number (676279674006).
Almost surely, 21352559348011 is an apocalyptic number.
1352559348011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1352559348011 is an equidigital number, since it uses as much as digits as its factorization.
1352559348011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 47.
The spelling of 1352559348011 in words is "one trillion, three hundred fifty-two billion, five hundred fifty-nine million, three hundred forty-eight thousand, eleven".
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