Base | Representation |
---|---|
bin | 10011101011110000111… |
… | …100000101010110100011 |
3 | 11210022110100012220122221 |
4 | 103223300330011112203 |
5 | 134130222433411342 |
6 | 2513223201211511 |
7 | 166504140256111 |
oct | 23536074052643 |
9 | 4708410186587 |
10 | 1352662013347 |
11 | 48172a496277 |
12 | 19a1a3930b97 |
13 | 9a72b510598 |
14 | 4967d660ab1 |
15 | 252bc349a67 |
hex | 13af0f055a3 |
1352662013347 has 2 divisors, whose sum is σ = 1352662013348. Its totient is φ = 1352662013346.
The previous prime is 1352662013281. The next prime is 1352662013369. The reversal of 1352662013347 is 7433102662531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1352662013347 - 235 = 1318302274979 is a prime.
It is a super-2 number, since 2×13526620133472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1352662013147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676331006673 + 676331006674.
It is an arithmetic number, because the mean of its divisors is an integer number (676331006674).
Almost surely, 21352662013347 is an apocalyptic number.
1352662013347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1352662013347 is an equidigital number, since it uses as much as digits as its factorization.
1352662013347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 43.
Adding to 1352662013347 its reverse (7433102662531), we get a palindrome (8785764675878).
The spelling of 1352662013347 in words is "one trillion, three hundred fifty-two billion, six hundred sixty-two million, thirteen thousand, three hundred forty-seven".
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