Base | Representation |
---|---|
bin | 11110110000011111010011… |
… | …000001111111101110110011 |
3 | 122201222000122021102201022001 |
4 | 132300133103001333232303 |
5 | 120212310200042101113 |
6 | 1155411445421354431 |
7 | 40331122212656212 |
oct | 3660372301775663 |
9 | 581860567381261 |
10 | 135273535503283 |
11 | 3a1142032439a1 |
12 | 13208b01408a17 |
13 | 5a63316700428 |
14 | 25593b9ddd079 |
15 | 1098b95e217dd |
hex | 7b07d307fbb3 |
135273535503283 has 4 divisors (see below), whose sum is σ = 139938140175840. Its totient is φ = 130608930830728.
The previous prime is 135273535503221. The next prime is 135273535503299. The reversal of 135273535503283 is 382305535372531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135273535503283 - 233 = 135264945568691 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135273538503283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2332302336235 + ... + 2332302336292.
It is an arithmetic number, because the mean of its divisors is an integer number (34984535043960).
Almost surely, 2135273535503283 is an apocalyptic number.
135273535503283 is a deficient number, since it is larger than the sum of its proper divisors (4664604672557).
135273535503283 is an equidigital number, since it uses as much as digits as its factorization.
135273535503283 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4664604672556.
The product of its (nonzero) digits is 34020000, while the sum is 55.
The spelling of 135273535503283 in words is "one hundred thirty-five trillion, two hundred seventy-three billion, five hundred thirty-five million, five hundred three thousand, two hundred eighty-three".
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