Base | Representation |
---|---|
bin | 111111000000010000… |
… | …1011111111001101001 |
3 | 110221020022021220110100 |
4 | 1332000201133321221 |
5 | 4204043331014431 |
6 | 142053413540013 |
7 | 12526603105611 |
oct | 1760041377151 |
9 | 427208256410 |
10 | 135300251241 |
11 | 52420512361 |
12 | 2227b944609 |
13 | c9b2cbb67c |
14 | 67973a7a41 |
15 | 37bd3284e6 |
hex | 1f8085fe69 |
135300251241 has 12 divisors (see below), whose sum is σ = 195459547140. Its totient is φ = 90188236320.
The previous prime is 135300251209. The next prime is 135300251257. The reversal of 135300251241 is 142152003531.
135300251241 is a `hidden beast` number, since 1 + 3 + 530 + 0 + 2 + 5 + 124 + 1 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 54100899216 + 81199352025 = 232596^2 + 284955^2 .
It is not a de Polignac number, because 135300251241 - 25 = 135300251209 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (135300251201) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 922170 + ... + 1058771.
It is an arithmetic number, because the mean of its divisors is an integer number (16288295595).
Almost surely, 2135300251241 is an apocalyptic number.
It is an amenable number.
135300251241 is a deficient number, since it is larger than the sum of its proper divisors (60159295899).
135300251241 is a wasteful number, since it uses less digits than its factorization.
135300251241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1988536 (or 1988533 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 135300251241 its reverse (142152003531), we get a palindrome (277452254772).
The spelling of 135300251241 in words is "one hundred thirty-five billion, three hundred million, two hundred fifty-one thousand, two hundred forty-one".
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