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13530312401051 = 68909196350439
BaseRepresentation
bin1100010011100100010101…
…1101101110000010011011
31202220111002201211202120102
43010321011131232002123
53233140034433313201
644435423435450015
72564350516546115
oct304710535560233
952814081752512
1013530312401051
11434719a685806
1216263222b690b
13771b97b1b774
1434ac28d743b5
15186e4b55226b
hexc4e4576e09b

13530312401051 has 4 divisors (see below), whose sum is σ = 13530508820400. Its totient is φ = 13530115981704.

The previous prime is 13530312400963. The next prime is 13530312401093. The reversal of 13530312401051 is 15010421303531.

13530312401051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13530312401051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13530312401351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98106311 + ... + 98244128.

It is an arithmetic number, because the mean of its divisors is an integer number (3382627205100).

Almost surely, 213530312401051 is an apocalyptic number.

13530312401051 is a deficient number, since it is larger than the sum of its proper divisors (196419349).

13530312401051 is an equidigital number, since it uses as much as digits as its factorization.

13530312401051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 196419348.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 13530312401051 its reverse (15010421303531), we get a palindrome (28540733704582).

The spelling of 13530312401051 in words is "thirteen trillion, five hundred thirty billion, three hundred twelve million, four hundred one thousand, fifty-one".

Divisors: 1 68909 196350439 13530312401051