Base | Representation |
---|---|
bin | 11001001101000010… |
… | …00110111000100001 |
3 | 1021221000011212022221 |
4 | 30212201012320201 |
5 | 210202431140131 |
6 | 10114402431041 |
7 | 656212402663 |
oct | 144641067041 |
9 | 37830155287 |
10 | 13531115041 |
11 | 5813a64004 |
12 | 2757662481 |
13 | 137842c462 |
14 | 925100533 |
15 | 542db4411 |
hex | 326846e21 |
13531115041 has 4 divisors (see below), whose sum is σ = 13532573572. Its totient is φ = 13529656512.
The previous prime is 13531114979. The next prime is 13531115057. The reversal of 13531115041 is 14051113531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12883158016 + 647957025 = 113504^2 + 25455^2 .
It is a cyclic number.
It is not a de Polignac number, because 13531115041 - 223 = 13522726433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13531114997 and 13531115015.
It is not an unprimeable number, because it can be changed into a prime (13531115341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715260 + ... + 733933.
It is an arithmetic number, because the mean of its divisors is an integer number (3383143393).
Almost surely, 213531115041 is an apocalyptic number.
It is an amenable number.
13531115041 is a deficient number, since it is larger than the sum of its proper divisors (1458531).
13531115041 is an equidigital number, since it uses as much as digits as its factorization.
13531115041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1458530.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 13531115041 its reverse (14051113531), we get a palindrome (27582228572).
The spelling of 13531115041 in words is "thirteen billion, five hundred thirty-one million, one hundred fifteen thousand, forty-one".
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