Base | Representation |
---|---|
bin | 11001001101000010… |
… | …01001000101110001 |
3 | 1021221000012022201202 |
4 | 30212201021011301 |
5 | 210202431432311 |
6 | 10114402540545 |
7 | 656212441226 |
oct | 144641110561 |
9 | 37830168652 |
10 | 13531124081 |
11 | 5813a6a882 |
12 | 2757667755 |
13 | 13784335c7 |
14 | 92510394d |
15 | 542db6e3b |
hex | 326849171 |
13531124081 has 2 divisors, whose sum is σ = 13531124082. Its totient is φ = 13531124080.
The previous prime is 13531124071. The next prime is 13531124129. The reversal of 13531124081 is 18042113531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7821810481 + 5709313600 = 88441^2 + 75560^2 .
It is a cyclic number.
It is not a de Polignac number, because 13531124081 - 222 = 13526929777 is a prime.
It is a super-2 number, since 2×135311240812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13531124051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765562040 + 6765562041.
It is an arithmetic number, because the mean of its divisors is an integer number (6765562041).
Almost surely, 213531124081 is an apocalyptic number.
It is an amenable number.
13531124081 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531124081 is an equidigital number, since it uses as much as digits as its factorization.
13531124081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 29.
The spelling of 13531124081 in words is "thirteen billion, five hundred thirty-one million, one hundred twenty-four thousand, eighty-one".
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