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13531361213401 is a prime number
BaseRepresentation
bin1100010011101000001111…
…1110100111101111011001
31202220120210211100221122021
43010322003332213233121
53233144211432312101
644440115503254441
72564415513400063
oct304720376475731
952816724327567
1013531361213401
114347688708a79
1216265755aa421
137720041b95a5
1434acc838a733
15186ead6765a1
hexc4e83fa7bd9

13531361213401 has 2 divisors, whose sum is σ = 13531361213402. Its totient is φ = 13531361213400.

The previous prime is 13531361213327. The next prime is 13531361213453. The reversal of 13531361213401 is 10431216313531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8781140963401 + 4750220250000 = 2963299^2 + 2179500^2 .

It is a cyclic number.

It is not a de Polignac number, because 13531361213401 - 215 = 13531361180633 is a prime.

It is not a weakly prime, because it can be changed into another prime (13531361213101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765680606700 + 6765680606701.

It is an arithmetic number, because the mean of its divisors is an integer number (6765680606701).

Almost surely, 213531361213401 is an apocalyptic number.

It is an amenable number.

13531361213401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531361213401 is an equidigital number, since it uses as much as digits as its factorization.

13531361213401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 34.

Adding to 13531361213401 its reverse (10431216313531), we get a palindrome (23962577526932).

The spelling of 13531361213401 in words is "thirteen trillion, five hundred thirty-one billion, three hundred sixty-one million, two hundred thirteen thousand, four hundred one".