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1353141235241 is a prime number
BaseRepresentation
bin10011101100001101100…
…000001010111000101001
311210100200201221220111222
4103230031200022320221
5134132213124011431
62513342520431425
7166522046503355
oct23541540127051
94710621856458
101353141235241
11481955a50824
1219a2b8318575
139a7a689c033
14496c7168465
15252e945b57b
hex13b0d80ae29

1353141235241 has 2 divisors, whose sum is σ = 1353141235242. Its totient is φ = 1353141235240.

The previous prime is 1353141235223. The next prime is 1353141235253. The reversal of 1353141235241 is 1425321413531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1352345713216 + 795522025 = 1162904^2 + 28205^2 .

It is a cyclic number.

It is not a de Polignac number, because 1353141235241 - 218 = 1353140973097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1353141235741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676570617620 + 676570617621.

It is an arithmetic number, because the mean of its divisors is an integer number (676570617621).

Almost surely, 21353141235241 is an apocalyptic number.

It is an amenable number.

1353141235241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353141235241 is an equidigital number, since it uses as much as digits as its factorization.

1353141235241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 35.

Adding to 1353141235241 its reverse (1425321413531), we get a palindrome (2778462648772).

The spelling of 1353141235241 in words is "one trillion, three hundred fifty-three billion, one hundred forty-one million, two hundred thirty-five thousand, two hundred forty-one".