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1353255154131 = 31319341990183
BaseRepresentation
bin10011101100010100010…
…010101111000111010011
311210100222200022120212010
4103230110102233013103
5134132431304413011
62513402110234003
7166524632006406
oct23542422570723
94710880276763
101353255154131
11481a04289771
1219a32a4b5903
139a7c437706a
14496d833dd3d
15253044601a6
hex13b144af1d3

1353255154131 has 8 divisors (see below), whose sum is σ = 1805708171520. Its totient is φ = 901486119752.

The previous prime is 1353255154081. The next prime is 1353255154151. The reversal of 1353255154131 is 1314515523531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1353255154131 - 27 = 1353255154003 is a prime.

It is a super-2 number, since 2×13532551541312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1353255154131.

It is not an unprimeable number, because it can be changed into a prime (1353255154151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170991135 + ... + 170999048.

It is an arithmetic number, because the mean of its divisors is an integer number (225713521440).

Almost surely, 21353255154131 is an apocalyptic number.

1353255154131 is a deficient number, since it is larger than the sum of its proper divisors (452453017389).

1353255154131 is a wasteful number, since it uses less digits than its factorization.

1353255154131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 341991505.

The product of its digits is 135000, while the sum is 39.

The spelling of 1353255154131 in words is "one trillion, three hundred fifty-three billion, two hundred fifty-five million, one hundred fifty-four thousand, one hundred thirty-one".

Divisors: 1 3 1319 3957 341990183 1025970549 451085051377 1353255154131