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1353255222113 = 6412111162593
BaseRepresentation
bin10011101100010100010…
…010111111101101100001
311210100222200110001002222
4103230110102333231201
5134132431314101423
62513402111520425
7166524632411534
oct23542422775541
94710880401088
101353255222113
11481a04325853
1219a32a529115
139a7c439bca2
14496d835aa1b
15253044753c8
hex13b144bfb61

1353255222113 has 4 divisors (see below), whose sum is σ = 1355366385348. Its totient is φ = 1351144058880.

The previous prime is 1353255222037. The next prime is 1353255222119. The reversal of 1353255222113 is 3112225523531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1076754878224 + 276500343889 = 1037668^2 + 525833^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1353255222113 is a prime.

It is a super-2 number, since 2×13532552221132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1353255222119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1055580656 + ... + 1055581937.

It is an arithmetic number, because the mean of its divisors is an integer number (338841596337).

Almost surely, 21353255222113 is an apocalyptic number.

It is an amenable number.

1353255222113 is a deficient number, since it is larger than the sum of its proper divisors (2111163235).

1353255222113 is an equidigital number, since it uses as much as digits as its factorization.

1353255222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2111163234.

The product of its digits is 54000, while the sum is 35.

The spelling of 1353255222113 in words is "one trillion, three hundred fifty-three billion, two hundred fifty-five million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 641 2111162593 1353255222113