Base | Representation |
---|---|
bin | 1100010011101111001011… |
… | …0110101011011100110011 |
3 | 1202220202121110122100020211 |
4 | 3010323302312223130303 |
5 | 3233212014134334134 |
6 | 44441024233444551 |
7 | 2564512561626505 |
oct | 304736266533463 |
9 | 52822543570224 |
10 | 13533221402419 |
11 | 4348452742574 |
12 | 16269b4570757 |
13 | 77223c6c1654 |
14 | 34b02344dd75 |
15 | 18706bb1d764 |
hex | c4ef2dab733 |
13533221402419 has 4 divisors (see below), whose sum is σ = 13545208313560. Its totient is φ = 13521234491280.
The previous prime is 13533221402399. The next prime is 13533221402563. The reversal of 13533221402419 is 91420412233531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13533221402419 - 25 = 13533221402387 is a prime.
It is a super-2 number, since 2×135332214024192 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13533221412419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5993453877 + ... + 5993456134.
It is an arithmetic number, because the mean of its divisors is an integer number (3386302078390).
Almost surely, 213533221402419 is an apocalyptic number.
13533221402419 is a deficient number, since it is larger than the sum of its proper divisors (11986911141).
13533221402419 is a wasteful number, since it uses less digits than its factorization.
13533221402419 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11986911140.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 13533221402419 in words is "thirteen trillion, five hundred thirty-three billion, two hundred twenty-one million, four hundred two thousand, four hundred nineteen".
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