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135332680832441 = 584392315793919
BaseRepresentation
bin11110110001010110011000…
…010111100001010110111001
3122202011200022012210202001122
4132301112120113201112321
5120214242312243114231
61155454550355155025
740335314663660201
oct3661263027412671
9582150265722048
10135332680832441
113a1372a423a114
1213218468ba5a75
135a68a81075311
14255c1cb175401
15109a4a85ed77b
hex7b15985e15b9

135332680832441 has 4 divisors (see below), whose sum is σ = 135334996684800. Its totient is φ = 135330364980084.

The previous prime is 135332680832387. The next prime is 135332680832449. The reversal of 135332680832441 is 144238086233531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135332680832441 - 238 = 135057802925497 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135332680832449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1157838521 + ... + 1157955398.

It is an arithmetic number, because the mean of its divisors is an integer number (33833749171200).

Almost surely, 2135332680832441 is an apocalyptic number.

It is an amenable number.

135332680832441 is a deficient number, since it is larger than the sum of its proper divisors (2315852359).

135332680832441 is an equidigital number, since it uses as much as digits as its factorization.

135332680832441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2315852358.

The product of its (nonzero) digits is 9953280, while the sum is 53.

The spelling of 135332680832441 in words is "one hundred thirty-five trillion, three hundred thirty-two billion, six hundred eighty million, eight hundred thirty-two thousand, four hundred forty-one".

Divisors: 1 58439 2315793919 135332680832441