Base | Representation |
---|---|
bin | 11001001101010100… |
… | …00110111010001010 |
3 | 1021221011121201211011 |
4 | 30212222012322022 |
5 | 210204032140232 |
6 | 10114525154134 |
7 | 656241430465 |
oct | 144652067212 |
9 | 37834551734 |
10 | 13533474442 |
11 | 5815325724 |
12 | 27583bb94a |
13 | 1378a77357 |
14 | 9255562dc |
15 | 5431cd547 |
hex | 326a86e8a |
13533474442 has 4 divisors (see below), whose sum is σ = 20300211666. Its totient is φ = 6766737220.
The previous prime is 13533474431. The next prime is 13533474443. The reversal of 13533474442 is 24447433531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24447433531 = 2557 ⋅9560983.
It can be written as a sum of positive squares in only one way, i.e., 13390886961 + 142587481 = 115719^2 + 11941^2 .
It is a super-2 number, since 2×135334744422 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13533474395 and 13533474404.
It is not an unprimeable number, because it can be changed into a prime (13533474443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3383368609 + ... + 3383368612.
Almost surely, 213533474442 is an apocalyptic number.
13533474442 is a deficient number, since it is larger than the sum of its proper divisors (6766737224).
13533474442 is an equidigital number, since it uses as much as digits as its factorization.
13533474442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6766737223.
The product of its digits is 483840, while the sum is 40.
The spelling of 13533474442 in words is "thirteen billion, five hundred thirty-three million, four hundred seventy-four thousand, four hundred forty-two".
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