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1353351241051 is a prime number
BaseRepresentation
bin10011101100011010000…
…001010001110101011011
311210101020101010022022221
4103230122001101311123
5134133130404203201
62513415421524511
7166530206513245
oct23543201216533
94711211108287
101353351241051
11481a53548247
1219a356713737
139a80b24a724
1449706dd3095
152530cae04a1
hex13b1a051d5b

1353351241051 has 2 divisors, whose sum is σ = 1353351241052. Its totient is φ = 1353351241050.

The previous prime is 1353351241031. The next prime is 1353351241087. The reversal of 1353351241051 is 1501421533531.

It is a weak prime.

It is an emirp because it is prime and its reverse (1501421533531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1353351241051 - 25 = 1353351241019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1353351240998 and 1353351241016.

It is not a weakly prime, because it can be changed into another prime (1353351241031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676675620525 + 676675620526.

It is an arithmetic number, because the mean of its divisors is an integer number (676675620526).

Almost surely, 21353351241051 is an apocalyptic number.

1353351241051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353351241051 is an equidigital number, since it uses as much as digits as its factorization.

1353351241051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 34.

Adding to 1353351241051 its reverse (1501421533531), we get a palindrome (2854772774582).

The spelling of 1353351241051 in words is "one trillion, three hundred fifty-three billion, three hundred fifty-one million, two hundred forty-one thousand, fifty-one".