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135335441 is a prime number
BaseRepresentation
bin10000001000100…
…00111000010001
3100102122202022202
420010100320101
5234121213231
621232412545
73232221653
oct1004207021
9312582282
10135335441
116a43657a
12393a7155
1322066157
1413d8c6d3
15bd345cb
hex8110e11

135335441 has 2 divisors, whose sum is σ = 135335442. Its totient is φ = 135335440.

The previous prime is 135335437. The next prime is 135335471. The reversal of 135335441 is 144533531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133171600 + 2163841 = 11540^2 + 1471^2 .

It is an emirp because it is prime and its reverse (144533531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135335441 - 22 = 135335437 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (135335471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67667720 + 67667721.

It is an arithmetic number, because the mean of its divisors is an integer number (67667721).

Almost surely, 2135335441 is an apocalyptic number.

It is an amenable number.

135335441 is a deficient number, since it is larger than the sum of its proper divisors (1).

135335441 is an equidigital number, since it uses as much as digits as its factorization.

135335441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10800, while the sum is 29.

The square root of 135335441 is about 11633.3761651552. The cubic root of 135335441 is about 513.4173185331.

Adding to 135335441 its reverse (144533531), we get a palindrome (279868972).

The spelling of 135335441 in words is "one hundred thirty-five million, three hundred thirty-five thousand, four hundred forty-one".