Base | Representation |
---|---|
bin | 11110110001011010110010… |
… | …010001011111100010011011 |
3 | 122202012010111211101001010210 |
4 | 132301122302101133202123 |
5 | 120214332004032131120 |
6 | 1155501051550542203 |
7 | 40335543123604545 |
oct | 3661326221374233 |
9 | 582163454331123 |
10 | 135337410427035 |
11 | 3a139300a46583 |
12 | 13219368b07963 |
13 | 5a69355b986bb |
14 | 255c519368695 |
15 | 109a68393ece0 |
hex | 7b16b245f89b |
135337410427035 has 16 divisors (see below), whose sum is σ = 216615543524640. Its totient is φ = 72154723280640.
The previous prime is 135337410427027. The next prime is 135337410427049. The reversal of 135337410427035 is 530724014733531.
It is not a de Polignac number, because 135337410427035 - 23 = 135337410427027 is a prime.
It is a super-2 number, since 2×1353374104270352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1576764850 + ... + 1576850679.
It is an arithmetic number, because the mean of its divisors is an integer number (13538471470290).
Almost surely, 2135337410427035 is an apocalyptic number.
135337410427035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135337410427035 is a deficient number, since it is larger than the sum of its proper divisors (81278133097605).
135337410427035 is a wasteful number, since it uses less digits than its factorization.
135337410427035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3153618398.
The product of its (nonzero) digits is 3175200, while the sum is 48.
The spelling of 135337410427035 in words is "one hundred thirty-five trillion, three hundred thirty-seven billion, four hundred ten million, four hundred twenty-seven thousand, thirty-five".
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