Base | Representation |
---|---|
bin | 1100010011110011000001… |
… | …0010100110001100101011 |
3 | 1202220212021022010210012201 |
4 | 3010330300102212030223 |
5 | 3233221122021143430 |
6 | 44441314413521031 |
7 | 2564550245652442 |
oct | 304746022461453 |
9 | 52825238123181 |
10 | 13534252131115 |
11 | 4348931544271 |
12 | 16270417a3177 |
13 | 7723750ca3a1 |
14 | 34b0c02b9d59 |
15 | 1870cc36e8ca |
hex | c4f304a632b |
13534252131115 has 16 divisors (see below), whose sum is σ = 16637356766016. Its totient is φ = 10563236352000.
The previous prime is 13534252131073. The next prime is 13534252131131. The reversal of 13534252131115 is 51113125243531.
It is not a de Polignac number, because 13534252131115 - 227 = 13534117913387 is a prime.
It is a super-2 number, since 2×135342521311152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49330315 + ... + 49603915.
It is an arithmetic number, because the mean of its divisors is an integer number (1039834797876).
Almost surely, 213534252131115 is an apocalyptic number.
13534252131115 is a deficient number, since it is larger than the sum of its proper divisors (3103104634901).
13534252131115 is a wasteful number, since it uses less digits than its factorization.
13534252131115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 514950.
The product of its digits is 54000, while the sum is 37.
Adding to 13534252131115 its reverse (51113125243531), we get a palindrome (64647377374646).
The spelling of 13534252131115 in words is "thirteen trillion, five hundred thirty-four billion, two hundred fifty-two million, one hundred thirty-one thousand, one hundred fifteen".
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