1353612334121 has 4 divisors (see below), whose sum is σ = 1356369182544. Its totient is φ = 1350855485700.

The previous prime is 1353612334103. The next prime is 1353612334153. The reversal of 1353612334121 is 1214332163531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1353612334121 - 2¹⁰ = 1353612333097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1353612334181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1378423475 + ... + 1378424456.

It is an arithmetic number, because the mean of its divisors is an integer number (339092295636).

Almost surely, 2^{1353612334121} is an apocalyptic number.

It is an amenable number.

1353612334121 is a deficient number, since it is larger than the sum of its proper divisors (2756848423).

1353612334121 is an equidigital number, since it uses as much as digits as its factorization.

1353612334121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2756848422.

The product of its digits is 38880, while the sum is 35.

Adding to 1353612334121 its reverse (1214332163531), we get a palindrome (2567944497652).

The spelling of 1353612334121 in words is "one trillion, three hundred fifty-three billion, six hundred twelve million, three hundred thirty-four thousand, one hundred twenty-one".