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13540043553 = 34513347851
BaseRepresentation
bin11001001110000110…
…01010101100100001
31021221121222110221120
430213003022230201
5210212222343203
610115322042453
7656351320431
oct144703125441
937847873846
1013540043553
115819002143
12275a649429
13137a2373ba
149263862c1
15543a79b53
hex3270cab21

13540043553 has 4 divisors (see below), whose sum is σ = 18053391408. Its totient is φ = 9026695700.

The previous prime is 13540043509. The next prime is 13540043623. The reversal of 13540043553 is 35534004531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13540043553 - 213 = 13540035361 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13540043353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2256673923 + ... + 2256673928.

It is an arithmetic number, because the mean of its divisors is an integer number (4513347852).

Almost surely, 213540043553 is an apocalyptic number.

It is an amenable number.

13540043553 is a deficient number, since it is larger than the sum of its proper divisors (4513347855).

13540043553 is an equidigital number, since it uses as much as digits as its factorization.

13540043553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4513347854.

The product of its (nonzero) digits is 54000, while the sum is 33.

The spelling of 13540043553 in words is "thirteen billion, five hundred forty million, forty-three thousand, five hundred fifty-three".

Divisors: 1 3 4513347851 13540043553