Base | Representation |
---|---|
bin | 10011101101000001010… |
… | …111100110100010001111 |
3 | 11210102221101100002020111 |
4 | 103231001113212202033 |
5 | 134141003404420211 |
6 | 2514005123300451 |
7 | 166552444016650 |
oct | 23550127464217 |
9 | 4712841302214 |
10 | 1354011404431 |
11 | 482262158814 |
12 | 19a4bb81a727 |
13 | 9a8b4c4c74a |
14 | 4976a95b527 |
15 | 2534aa44421 |
hex | 13b415e688f |
1354011404431 has 16 divisors (see below), whose sum is σ = 1569348933120. Its totient is φ = 1144153049760.
The previous prime is 1354011404401. The next prime is 1354011404443. The reversal of 1354011404431 is 1344041104531.
It is not a de Polignac number, because 1354011404431 - 25 = 1354011404399 is a prime.
It is a super-2 number, since 2×13540114044312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1354011404393 and 1354011404402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1354011404401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7434105 + ... + 7614061.
It is an arithmetic number, because the mean of its divisors is an integer number (98084308320).
Almost surely, 21354011404431 is an apocalyptic number.
1354011404431 is a deficient number, since it is larger than the sum of its proper divisors (215337528689).
1354011404431 is a wasteful number, since it uses less digits than its factorization.
1354011404431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 195174.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1354011404431 its reverse (1344041104531), we get a palindrome (2698052508962).
The spelling of 1354011404431 in words is "one trillion, three hundred fifty-four billion, eleven million, four hundred four thousand, four hundred thirty-one".
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