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13540154323 = 61947923417
BaseRepresentation
bin11001001110000111…
…00101101111010011
31021221122012002220011
430213003211233103
5210212234414243
610115324255351
7656352261403
oct144703455723
937848162804
1013540154323
115819078393
12275a6a1557
13137a275947
149263b4803
15543a9c89d
hex3270e5bd3

13540154323 has 8 divisors (see below), whose sum is σ = 13764163680. Its totient is φ = 13316210880.

The previous prime is 13540154311. The next prime is 13540154389. The reversal of 13540154323 is 32345104531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13540154323 - 221 = 13538057171 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13540154123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 566511 + ... + 589927.

It is an arithmetic number, because the mean of its divisors is an integer number (1720520460).

Almost surely, 213540154323 is an apocalyptic number.

13540154323 is a deficient number, since it is larger than the sum of its proper divisors (224009357).

13540154323 is an equidigital number, since it uses as much as digits as its factorization.

13540154323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32957.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13540154323 its reverse (32345104531), we get a palindrome (45885258854).

The spelling of 13540154323 in words is "thirteen billion, five hundred forty million, one hundred fifty-four thousand, three hundred twenty-three".

Divisors: 1 61 9479 23417 578219 1428437 221969743 13540154323